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SOLVED:A steel ball-bearing with a circumference of 32.5 \mathrm{mm} weighs 4.20 \mathrm{g} . What is the density of the steel in \mathrm{g} / \mathrm{cm}^{3}(\mathrm{V} \text { of a sphere }= \frac{4}{3} \pi
SOLVED:A steel ball-bearing with a circumference of 32.5 \mathrm{mm} weighs 4.20 \mathrm{g} . What is the density of the steel in \mathrm{g} / \mathrm{cm}^{3}(\mathrm{V} \text { of a sphere }= \frac{4}{3} \pi
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